((x-5)/(x^2+2x-3))-((x-1)/(x^2+6x+9))

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Solution for ((x-5)/(x^2+2x-3))-((x-1)/(x^2+6x+9)) equation: 


D( x )

x^2+6*x+9 = 0

x^2+2*x-3 = 0

x^2+6*x+9 = 0

x^2+6*x+9 = 0

x^2+6*x+9 = 0

DELTA = 6^2-(1*4*9)

DELTA = 0

x = -6/(1*2)

x = -3 or x = -3

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

x in (-oo:-3) U (-3:1) U (1:+oo)

(x-5)/(x^2+2*x-3)-((x-1)/(x^2+6*x+9)) = 0

(x-5)/(x^2+2*x-3)+(-1*(x-1))/(x^2+6*x+9) = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

(x+3)*(x-1) = 0

x^2+6*x+9 = 0

x^2+6*x+9 = 0

x^2+6*x+9 = 0

DELTA = 6^2-(1*4*9)

DELTA = 0

x = -6/(1*2)

x = -3 or x = -3

(x+3)^2 = 0

(x-5)/((x+3)*(x-1))+(-1*(x-1))/((x+3)^2) = 0

((x-5)*(x+3))/((x+3)^2*(x-1))+(-1*(x-1)^2)/((x+3)^2*(x-1)) = 0

(x-5)*(x+3)-1*(x-1)^2 = 0

-16 = 0

-16/((x+3)^2*(x-1)) = 0

-16/((x+3)^2*(x-1)) = 0 // * (x+3)^2*(x-1)

-16 = 0

x belongs to the empty set

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